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9m^2+42m=-49
We move all terms to the left:
9m^2+42m-(-49)=0
We add all the numbers together, and all the variables
9m^2+42m+49=0
a = 9; b = 42; c = +49;
Δ = b2-4ac
Δ = 422-4·9·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{-42}{18}=-2+1/3$
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